Question

A 60Kg man is inside a lift which is moving up with an acceleration of 2.45 m/sec2. The apparent percentage change in his weight is

Answer 1

Original weight is 60×9.8 = 588N
Now as man is inside lift and it is moving up so
apparent weight can be given as :
Apparent weight = m×(g-a) N
= 60×(9.8-2.45) = 441N
So weight change = (441/588)×100 = 75%

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