A 60kg man stands on the middle of a 20kg ladder as shown in fig, reaction at A will be?
Answers
Explanation:
Reaction at A will be 3 m 60+20 rim 1.5 m Fig.
Answer:
The reaction force at point A will be 784 N.
Explanation:
As there is no figure provided, let's assume the ladder is placed horizontally and the man is standing in the middle of the ladder.
The ladder is in equilibrium, which means the forces acting on it should balance each other. The forces acting on the ladder are the weight of the ladder and the weight of the man acting downward and the reaction force at point A acting upward.
The weight of the ladder (W1) can be calculated as:
W1 = m1 * g
= 20 kg * 9.8 m/s^2
= 196 N
The weight of the man (W2) can be calculated as:
W2 = m2 * g
= 60 kg * 9.8 m/s^2
= 588 N
The total weight acting on the ladder is the sum of W1 and W2:
W = W1 + W2
= 196 N + 588 N
= 784 N
As the ladder is in equilibrium, the reaction force at point A should be equal to the weight acting on the ladder, which is 784 N.
Therefore, the reaction force at point A will be 784 N.
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