A 60L solution of acid and water contains 15L of acid. How much water should be added so that the solution has 12% acid?
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0
Answer:
60
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Answered by
3
Answer:
let's "x" liters of 35% acid solution is required to be added
Then
Total mixture = (x + 600) liters.
Therefore ,
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AND
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so
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Thus, the no. of liters of the 30% solutions of acid will have to be more than 120 liters but less then 300 liters.
Step-by-step explanation:
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