Physics, asked by Ruchabonde, 11 months ago

A 60W bulb is switched on for 5hr daily.if the cost of electricity is Rs3 per unit, calculate the bill for the month of april​

Answers

Answered by debojitsahu999
1

Answer:

Rs.27

Explanation:

Energy consumed by the bulb daily

=60W × 5h

=300 Wh

Energy consumed in the month of April is 300 Wh×30

=9000 Wh

=9 kWh

cost = 9 kWh×Rs.3

       = Rs.27

Answered by Anonymous
18

\huge{\underline{\underline{\bf{Solution}}}}

\rule{200}{2}

  \tt Given \begin{cases}  \sf{Time taken = 5 \: Hrs} \\ \sf{Power \: of \: bulb = 60 \: w} \\ \sf{Cost \: per \: unit = 3 Rs.} \\ \sf{Number \: of \: days = 30} \end{cases}

\rule{200}{2}

\Large{\underline{\underline{\bf{To \: Find :}}}}

We have to find the bill in April month

\rule{200}{2}

\Large{\underline{\underline{\bf{Explanation :}}}}

We know the formula to find the enegy

\large{\star{\boxed{\sf{Energy = Power \times time}}}}

_______________[Put Values]

\sf{\mapsto Energy = 60 \times 5 \times 30} \\ \\ \sf{\mapsto Energy = 300 \times 30} \\ \\ \sf{\mapsto 9000 \: Wh} \\ \\ \bf{Converting \: into kWh} \\ \\ \sf{Energy = 9 \: kWh}

\large{\star{\boxed{\sf{Energy = 9 \: kWh}}}}

\rule{200}{2}

\large{\star{\boxed{\sf{Total \: cost = Energy \times cost \: per \: unit}}}}

\sf{\mapsto Total \: cost = 9 \times 3} \\ \\ \sf{\mapsto Total \: cost = 27 \: Rs.}

\therefore Bill for april month is 27.

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