Question

a 60watt light bulb has a current of 0.5 passing through it calculate number of electron passing cross-section of the bulb?​

Answer 1

Answer:

1.125×10^22 electrons per hour

Explanation:

we know that,

q=It. where q=charge, I=current(0.5A), t= time(1 hour)

q=0.5×3600 (3600 sec)

=1800 C

Now,.

q=ne. where q= charge(1800C),n=no. of electrons

and e=charge on electron(1.6×10^-19C)

1800=n×1.6×10^-19

n= 1800÷1.6×10-19

n=1.125×10^22 electrons per hour

mark as BRAINLIEST