Question

(a) 62 and 124
HCF Using Common division method
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Answer 1

Answer:

Divide the larger number by the smaller one.

Divide the larger number by the smaller one.Notice that dividing our numbers leaves no remainder:

Divide the larger number by the smaller one.Notice that dividing our numbers leaves no remainder:124 ÷ 62 = 2 + 0;

Divide the larger number by the smaller one.Notice that dividing our numbers leaves no remainder:124 ÷ 62 = 2 + 0;=> 124 = 62 × 2;

Divide the larger number by the smaller one.Notice that dividing our numbers leaves no remainder:124 ÷ 62 = 2 + 0;=> 124 = 62 × 2;So, 124 is divisible by 62;

Divide the larger number by the smaller one.Notice that dividing our numbers leaves no remainder:124 ÷ 62 = 2 + 0;=> 124 = 62 × 2;So, 124 is divisible by 62;62 is a factor (a divisor) of 124;

Divide the larger number by the smaller one.Notice that dividing our numbers leaves no remainder:124 ÷ 62 = 2 + 0;=> 124 = 62 × 2;So, 124 is divisible by 62;62 is a factor (a divisor) of 124;Consequently, greatest (highest) common factor (divisor):

Divide the larger number by the smaller one.Notice that dividing our numbers leaves no remainder:124 ÷ 62 = 2 + 0;=> 124 = 62 × 2;So, 124 is divisible by 62;62 is a factor (a divisor) of 124;Consequently, greatest (highest) common factor (divisor):gcf, hcf, gcd (62; 124) = 62;