Question

A 62 m length of a rope is cut into pieces whose lengths are in a arithmetic progression with common difference of d. Given the length of the shortest and longest pieces are 0.5 m and 3.5 m respectively. Find the number of pieces and the value of d.

Answer 1

Answer:

n = 31 , d = 1/10 or 0.1   a.p. 0.5 , 0.6 , 0.7 .......     3.5

Step-by-step explanation:

sⁿ =n/2 *( FIRST TERM + LAST TERM )

62 = n/2 *( FIRST TERM + LAST TERM )

62 = n/2 *( 0.5 + 3.5 )

62 = n/2 *(4)

62 = 2*n

n = 62/2

n = 31

aⁿ =a + (n-1)d

3.5 = 0.5 +(31-1)d

3.5 = 0.5 + 30d

3.0 = 30d

d = 1/10 or 0.1