Question

A=62°,ABC=54°,find BOC​

Answer 1

Answer:

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Answer 2

Given,angle A= 62°

and ABC is equal to 54°

then, ACB= BAC+BCA+ABC= 180°

62+54+BCA=180°

so, BCA= 180°-116°=64°

now, given BO and CO are bisector of angle B and C

so in triangle OBC

54/2=27,

64/2=32

27+32+BOC= 180°

BOC=180-59=121°

angle OCB=64°

and angle OCB= 121°