Question

A 63.0kg astronaut throws a 5.0kg hammer in a direction away from the shuttle with a speed of 18.0m/s, pushing the astronaut back to the shuttle. Assuming that the astronaut and hammer start from rest, find the final speed of the astronaut after throwing the hammer​

Answer 1

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astronaut's weight = 63 kg

hammer's weight= 5 kg

speed of the hammer=18.0m/s

formula to find speed of astronaut after throwing the hammer:-

$\implies\boxed{\textsf{total \:initial \:momentum\:= total \:final\: momentum}}$

$\implies\boxed{\sf{m_1\;u_1+m_2\;u_2=m_1\;v_1+m_2\;v_2}}$

$⟶(63)(0)+(5)(0)=(63)v_A+(5)(18)$

$\longrightarrow\sf{0=63\;v_A+90}$

$⟶−90=63v_A$

$⟶ v_ A =−1.4285ms −1$

$\longrightarrow\underline{\underline{\red{\sf{v_A=-1.4285\;\;ms^{-1}}}}}$

therefore,

$⟶ v_ A =−1.4285ms −1$ is approx the final speed of the astronaut after throwing the hammer.