Question

A 63 liter mixture contains milk and water in a ratio of 4: 5. Then x liters of milk and y liters of water are added to the mixture, resulting in
60 ters of the mixture are drained and replaced with 60 liters of water, resulting in a milk to water ratio of 7:8 What is the value of x+y ?

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Answer 1

Given:

The $63$ liter mixture contains milk and water in a ratio of $4:5$ resulting in $60$liters of the mixture are drained and replaced with$60$ liters of water, resulting in a milk to water ratio of $7:8$.

To find:

The resulting in a milk the value of $x+y$.

Step-by-step explanation:

$4p+5p=63$

$p=7$

initially milk is $28$ liters and water is $35$ liters

$z=x+y$

The final volume is $(63+z)$

The volume of water before and after the last step.

$\frac{5}{12}(3+z)+60=\frac{8}{15}(63+z)$

$z=x+y=237$

Answer:

Therefore, The resulting in a milk of the value of $x+y=237$.