Math, asked by 17r21a05c3, 4 hours ago

A 63 liter mixture contains milk and water in a ratio of 4:5. Then xliters of milk and y liters of water are added to the mixture, resulting in a milk to water ratio of 7.5. Finally, 60 liters of the mixture are drained and replaced with 60 liters of water, resulting in a milk to water ratio of 7:8 What is the value of xy?

Answers

Answered by surekhareddy714
0

Correct option is

D

60

Ratio of  milk and water=2:1

2+1=3

Quantity of milk in mixture =  

3

2

×60=40L

Quantity of water=60−40=20

To make ratio 1:2 we add 60L water to the mixture.

40:80=1:2Step-by-step explanation:

Answered by GulabLachman
0

Correct Question -

A 63 liter mixture contains milk and water in a ratio of 4:5. Then xliters of milk and y liters of water are added to the mixture, resulting in a milk to water ratio of 7.5. Finally, 60 liters of the mixture are drained and replaced with 60 liters of water, resulting in a milk to water ratio of 7:8 What is the value of x + y?

The value of x + y is 237

Given:

Quantity of mixture = 63L

Milk to water ratio = 4:5

Final milk to water ratio = 7:5

Quantity drained = 60L

Water replaced = 60L

New milk to water ratio = 7:8

To Find:

The value of x + y

Solution:

According to the question -

4p + 5p = 63

9p = 63

p = 7

Now,

Let z = x + y

Final Volume = 63 + z

The volume of water before and after all the combinations.

= 5/12 ( 3 + z) + 60 = 8/15 ( 63 + z) [ Final ratio = 7:5, new ratio = 7:8]

On solving we will get -

= x + y = 237

Answer: The value of x + y is 237

#SPJ2

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