Question

A 63 liter mixture contains milk and water in a ratio of 4:5. then x liters of milk and y liters of water are added to the mixture, resulting in a milk to water ratio of 7:5. finally , 60 liters of the mixture are drained and replaced with 60 liters of water, resulting in a milk to water ratio of 7:8. what is the value of x+y ?
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Answer 1

Answer:

milk=4*100/63 =6.34920635 , water=5*100/63=7.93650794.

Explanation:

Answer 2

Answer: A 63-liter mixture contains milk and water in a ratio of 4:5. then x liters of milk and y liters of water are added to the mixture, resulting in a milk-to-water ratio of 7:5. finally, 60 liters of the mixture are drained and replaced with 60 liters of water, resulting in a milk-to-water ratio of 7:8. what is the value of x+y = 6

Explanation:

Now here

Given the question,

Milk and Water ratio in 63-liter mixture = 4:5

Addition of extra milk and water  = 7:5

Now from the question

Let's assume that,

63 liter mixture = $\frac{milk}{water}$ =  $\frac{4}{5}$                         ..............(i)

After addition, the resulting mixture will be

63 liter mixture = $\frac{milk}{water}$ =  $\frac{7}{5}$                         ..............(ii)

after that,

60 liter of the mixture is drained out              ..............(iii)

and this drained mixture is replaced with the 60 liters of the water

Therefore, the ratio is changed to the,

63 liter mixture = $\frac{milk}{water}$ =  $\frac{7}{8}$                         ..............(iv))

Now by doing a quadratic equation here from above all equation we get,

4x + 5y = 63                    ......................(v)

7x + 5y = 60                    ......................(vi)

7x + 8y = 63                    ......................(vii)

Now by doing subtraction here we get the value

x = -1 and y = 6

Therefore value of x+y = 6

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