Question

A 64 bits wide main memory unit with a capacity of 4GB is built using 128M*8 bits Ram chip.How many Chips are required to construct the memory and how are chips arrangedA 64 bits wide main memory unit with a capacity of 4GB is built using 128M*8 bits Ram chip.How many Chips are required to construct the memory and how chips are arranged??​

Answer 1

Answer:

32 Chips are required to construct the memory and chips are arranged in a 4×8 hybrid arrangement.

Explanation:

64 bits wide main memory with a capacity of 4 GB, which means the total size of memory = 4GB
and each cell size = 64 bits.

4GB = 2² × 2¹⁰ MB = 2² × 2¹⁰ × 8 M bits = 2⁹ × 64 Mbits
[MB = MegaByte]

So, our memory representation would be = 2⁹ M × 64-bits

Given RAM chips = 128M × 8-bits = 2⁷ M × 8-bits.

So, the total no. of memory chips required is
= (2⁹ M × 64-bits)/ (2⁷ M × 8-bits.)
= 4×8
= 32 Chips.

so, the arrangement of the chips would be a 4×8 hybrid arrangement.

I think it will help you.

Answer 2

Answer:

Explanation:

Concept:

Memory definition:

Memory serves as the computer's electrical storage facility for the instructions and data that it needs to access fast. Information is kept there for quick access. A computer's memory is one of its fundamental components since without it, a computer would not be able to operate as intended.

RAM chip definition:

The physical component that houses the transistors necessary to perform random access memory in hardware is known as a RAM chip. As the fundamental building block for RAM cards and other applications, it is the most fundamental and essential component of memory.

Capacity of RAM:

RAM is manufactured as physical strips. There is a fixed amount of memory capacity available for each strip, ranging from $2$GB to $32$GB. The majority of laptop motherboards include two to three RAM slots. Your laptop probably uses two different $4$GB RAM strips in separate slots if it has $8$GB of RAM.

Given:

RAM chips $= 128M \times 8-bits$

Capacity$=4GB$

Memory$=64 bits$

Find:

We have to find the chips are required to construct the memory and how chips are arranged.

Solution:

Given that RAM chips $= 128M \times 8-bits$

                 Capacity$=4GB$

                 Memory$=64 bits$

The memory must be built from $32$ chips, which are placed in a hybrid $4\times8$ configuration.

primary memory that is $64$ bits wide and has a capacity of $4$ GB has a total memory size of $4$ GB and a cell size of $64$ bits..

$4GB = 2^2 \times 2^{10} MB$

       $= 2^{2} \times 2x^{10} \times 8 M bits$

      $= 2^{9} \times 64 Mbits$

Our memory representation would then be $= 2^{9} M \times 64-bits$

Given RAM chips $= 128M \times 8-bits$

                             $= 2^{7} M \times 8-bits.$

As a result, there are a total of memory chips needed.

$= (2^{9} M \times 64-bits)/ (2^{7} M \times 8-bits)$

$= 4\times8$

$= 32$ Chips.

$4\times 8$ hybrid configuration of the chips would be used.

Hence $4\times8$  hybrid configuration chips are required to construct the memory and how chips are arranged.

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