Question

A 64-kg woman stands on frictionless level ice with a 0.10-kg
. She kicks the stone with her foot so that she acquires a velocity of 0.0017 m/s. in the forward direction. The velocity acquired by the stone is:

Answer 1

Answer:

A 64-kg woman stands on frictionless level ice with a 0.10-kg tibeat ger feet. She kicks the stone with her foot so that she acquiresa velocity of 0.0017 m/s. in the forward direction. The velocityacquired by the stone is: 1.1 m/s forward. 1.1 m/s backward. 0.0017 m/s forward. 0.0017 m/s backward

Answer 2

Answer:

v= 1.088 m/s

Explanation:

Given that

Mass of women = 64 Kg

Mass of stone = 0.1 kg

Velocity of women = 0.0017 m/s

We know that if there is no any external force then linear momentum of system will be conserve.

Lets velocity of stone  after kicks by women = v

We know that linear momentum P = M .V

Initially Pi= 0

Pf= 64 x 0.0017 + 0.1 v

Pi=Pf

0= 64 x 0.0017 + 0.1 v

v= - 1.088 m/s

It means that stone will move with speed 1.088 m/s but in backward direction.