Question

A 64kb cache has 256 btye block size and 8 way set associative what is sizwe of tag

Answer 1

Let's assume the system is byte addressable. Then each cache block contains 8 words*(4 bytes/word)=32=25 bytes, so the offset is 5 bits. The index for a direct mapped cache is the number of blocks in the cache (12 bits in this case, because 212=4096.) Then the tag is all the bits that are left, as you have indicated.

Hope this helps you ☺️☺️✌️✌️❤️❤️