Question

A 65.7 g sample of an element contains 4.95×10²³ atoms. Identify the element?

Answer 1

Answer: The element is bromine

Explanation:

We have given:-

No.of atoms =4.95*10^23

Given weight =65.7

So we need to find molecular weight of the element so to know about the name of element...

We know that

No.of atoms =no of moles*Avogadro's no.

So ,

4.95*10^23=65.7/X *6*10^23

X=65.7*6*10^23/4.95*10^23

So, it is equal to 80

Therefore answer is bromine