Question

.A 65-kg swimmer pushes on the pool wall and accelerates at 6 m/s2. The friction experienced by the swimmer is 100 N. What is the magnitude of the force that the swimmer applies on the wall?

Answer 1

Given:

A 65-kg swimmer pushes on the pool wall and accelerates at 6 m/s². Friction experienced is 100 N.

To find:

Magnitude of force ?

Calculation:

• The net force will be the applied force - the friction.

• The applied force will be the force given by swimmer by pushing the wall of pool.

$F_{net} = F_{applied} - f$

$\implies \: ma = F_{applied} - 100$

$\implies \: (65 \times 6)= F_{applied} - 100$

$\implies \: F_{applied} = 100 + 390$

$\implies \: F_{applied} = 490 \:N$

So, force applied by swimmer is 490 N.