Question

A 650 kg rocket is to be speeded up from 440 ms¹ to 520 ms in outer space. If the thrust of the engine 1200 N, for how long must the engine be fired?​

Answer 1

Answer:

Force required to overcome the weight

F=mg=v  

dt

dm

​

 

dt

dm

​

=  

v

mg

​

 

=  

1000

600×9.8

​

=58.6kg/s

​

 

=58.6 kg/s

Hence, this is the answer.

Explanation:Hope it helps you mark me as the brainliest

Answer 2

Answer:

58.6kg/s should be fired

Explanation:

Force required to overcome the weight

F=mg=v  

dt*dm*dt

dm= v*mg

= 1000*600×9.8=58.6kg/s

=58.6 kg/s

For similar questions refer-https://brainly.in/question/15696252

#SPJ5