A 650 KW power engine of a vehicle of
mass 1.5 * 105 Kg is rising on an inclined plane of inclination
1 in 100 with a constant speed of 60 km/hr. Find the frictional
force between the wheels of the vehicle and the plane.
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Explanation:
Given A 650 KW power engine of a vehicle of mass 1.5 * 105 Kg is rising on an inclined plane of inclination 1 in 100 with a constant speed of 60 km/hr. Find the frictional force between the wheels of the vehicle and the plane.
- Engine Power P = 650 KW = 6,50,000 W
- Mass of vehicle = m = 1.5 x 10^5 kg
- Inclination sin theta = 1/100
- Speed V = 60 km/hr = 60 x 5 / 18 = 50 / 3 m/s
- We need to find the frictional force.
- F = f + mg sin theta (Now P = F V)
- P/V = f + 1.5 x 10^5 x 10 x 1/100
- 6,50,000 x 3 / 50 = f + 15000
- 39,000 – 15,000 = f
- Or f = 24,000 N
- So the frictional force between the wheels of the vehicle and the plane is 24,000 N
Reference link will be
https://brainly.in/question/5483095
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