A 660 W electric heater is designed to operate from 120 V lines. What is its resistance? What current does it draw? If the line voltage drops to 110 V what power does the heater take?
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Answered by
7
Answer:
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Explanation:
H
1
=500 W
V
1
=115 V
V
2
=110 V
From Joule's Law of heating,
H
1
=
R
(V
1
)
2
and H
2
=
R
(V
2
)
2
⇒R=
H
1
(V
1
)
2
=
H
2
(V
2
)
2
⇒H
2
=
V
1
2
V
2
2
H
1
∴H
2
=
(115)
2
(110)
2
(500)
∴H
2
=457.46W
The percentage drop in heat output will be:
H
1
H
2
−H
1
×100=
500
500−457.46
×100=
500
42.54
×100=8.5 %
Answered by
7
Answer:
a 660 W electric heater is designed to operate from 120 V lines. What is its resistance What current does it draw iif the line voularad
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