Question

a=67 b=68 then what is the value of q=? r=?
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Answer 1

Division algorithm.

Given integers $a$ and $b$ with $b>0$, there exist unique integers $q$ and $r$ such that $a=bq+r$, where $0\leqslant r<b$.

Step-by-step explanation:

• Here, $a=67$ and $b=68$.
• Thus we have: $67=68q+r$.
• When $q=1$ and $r=-1$, the above relation satisfies.
• Reason. $67=68\times 1+(-1)=68-1=67$.

Answer: $q=1,\:r=-1$.

Answer 2

Answer:

tq for the question u posted......