Question

(-a+6b-2c)^2 expand it please​

Answer 1

Step-by-step explanation:

$a ^{2} +36 b ^{2} +4 c ^{2} - 12ab - 24bc +4ca = 0$

it is in the form of (a+b+c )^2=a^2+b^2+c^2+2ab+2bc+2ca.....

I hope it helps you........

Answer 2

Answer:-

(-a+6b-2c)² = a² + 36b² +4c² -12ab -24bc +4ac.

Given:-

(-a + 6b -2c )²

To find :-

It's expands form.

Solution:-

We have an identity :-

★ $\boxed{\sf{(a + b + c) ^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca}}$

→$(-a +6b-2c)^2 = (-a) ^2 + (6b)^2 + (-2c)^2 + 2.(-a).6b + 2.6b.(-2c)+2.(-2c).(-a)$

→$(-a+6b-2c)^2 = a^2 + 36b^2 + 4c^2 -12ab -24bc +4ac$

hence,the expand form is :-

(-a+6b-2c)² = a² + 36b² +4c² -12ab -24bc +4ac.