Math, asked by rajkishorsonu97, 11 months ago

a=6c
2a+b=6c+d+2e
2b=12c+2d

Where,c=1,a=6
Find value of 'b' ,'d' and 'e'​

Answers

Answered by sureshsharma4084
0
we have .,,

2a+b=6c+d+2e
2(6)+b=6(1)+d+2e
12+b = 6+d+2e
12-6 =d+2e-b
d+2e-b =6

2b =12c+2d
2b -2d =12(1)
2(b-d) =12
b-d =12/2
b-d = 6

solve it now by urself!!
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