Question

A 6cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 15cm. The distance of the object from the lens is 10cm. Find the position, size and nature of the image formed, using the lens formula

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

position of image => 30cm

size of image => 18cm

nature of image => real and enlarged

Step-by-step explanation:

height of object = 6cm

focal length of convex lens, f = +15cm

object distance from the lens, u = -10cm

from lens maker formula,

1/v - 1/u = 1/f

1/v - 1/-10 = 1/15

or, 1/v = 1/15 - 1/10

or, 1/v = 2/30 - 3/30 = -1/30

or, v = -30cm

hence, position of image is 30cm aways from the lens.

magnification, m = v/u

or, height of image/height of object = v/u

or, height of image/6cm = (-30cm)/(-10cm)

or, height of image = 18cm

hence, height of image is 18cm ( larger than object )

so, position of image => 30cm

size of image => 18cm

nature of image => real and enlarged

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