A 6cm tall object is placed perpendicular to the principal axis of a concave mirror of focal length 30cm. The distance of the object from the mirror is 45cm. Find the position, nature and size of the image formed. ..............
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Answers
Answered by
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apply mirror formula
1/f=1/v+1/u
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Hii there,
● Answer -
Position => 90 cm behind mirror
Size => 12 cm
Nature => Virtual & erect image
● Explanation -
# Given -
u = -45 cm
h1 = 6 cm
f = -30 cm
# Solution -
Using mirror formula,
1/f = 1/v - 1/u
1/-30 = 1/v - 1/-45
v = -90 cm
Magnification by mirror is calculated by -
M = v/u = h2/h1
h2 = h1 × v / u
h2 = 6 × (-90) / (-45)
h2 = 12 cm
Therefore, virtual & erect image of size 12 cm is formed 90 cm behind concave mirror.
Hope this helped...
● Answer -
Position => 90 cm behind mirror
Size => 12 cm
Nature => Virtual & erect image
● Explanation -
# Given -
u = -45 cm
h1 = 6 cm
f = -30 cm
# Solution -
Using mirror formula,
1/f = 1/v - 1/u
1/-30 = 1/v - 1/-45
v = -90 cm
Magnification by mirror is calculated by -
M = v/u = h2/h1
h2 = h1 × v / u
h2 = 6 × (-90) / (-45)
h2 = 12 cm
Therefore, virtual & erect image of size 12 cm is formed 90 cm behind concave mirror.
Hope this helped...
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