A 6g pellet is fired from a 360g gun. If the speed of the recoiling gun is 10m/s, what is
the speed of the pellet?
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Answer:
Explanation:
mass of pellet(m)= 6g = 0.006kg , velocity of pellet(v) = ?
mass of gun(M) = 360g = 0.36kg , velocity of gun(V)= 10 m/s
mv = -MV (newton's third law)
substituting values,
0.006 x v = -0.36 x 10
v = -3.6/0.006 = -3600/6 = -600m/s
( note: negative sign indicates that the direction of motion of pellet is opposite to that of gun)
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