A 6kg ball strikes a vertical wall with a velocity
30m/s and rebounds with velocity of 20m/s. The
impulse is
1) 60Ns 2) 300NS 3) 48Ns 4) 360NS
Answers
Answer:
Explanation:
Solution,
Here, we have
Mass of ball, m = 6 kg
Initial velocity of ball, u = 30 m/s
Final velocity of ball, v = 20 m/s
To Find,
Impulse, I = ??
We know that
I = m × (v - u)
Putting all the values, we get
⇒ I = 6 × (20 - 30)
⇒ I = 6 × (- 10)
⇒ I = 60 N/s
Hence, The impulse is 60 N/s.
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✰Question ✰
⋄ A 6kg ball strikes a vertical wall with a velocity
30m/s and rebounds with velocity of 20m/s. The
impulse is
(1) 60Ns
(2) 300Ns
(3) 48Ns
(4) 360Ns
_______________________________
✰ Given:-
⋄ Mass of ball =6kg
⋄ initial velocity (u) = 30m/s
⋄ Final velocity (v) =20m/s
_______________________________
✰To Find:-
⋄ Impulse of ball??
_______________________________
✰Solution :-
By using Impulse Formula
➧ Impulse (I) = Force(f) ×Time (t)
➧ I = f × t ..............(i)
And, we know that,
➧ Force = mass × acceleration
➧ F = m× a
➧ f = m (v-u/t)×t............(ii)
Putting value of equation (ii) we get
➧ I = m× ( v-u/t) ×t
➧ I = 6 × (30-20)
➧ I = 6×10
➧ I = 60N/s
∴ The impulse of ball is 60N/s.
Hence option (a) is the correct answer.