Question

a 6kg bomb at rest explodes into 3 equal pieces p q r if p flies with velocity 30mps and q with speed 40mps making an angle 90 with direction of p. the angle between the direction of motion of p and r is about
options:
a. 143degree
b. 127degree
c.120degree
d.150degree

Answer 1

HELLO THERE!

Mass of the bomb is 6 kg, which explodes into three equal parts p, q, r. This tells that mass of p, q, and r are same, let it be m.

Assume that p has moved through the Y-axis and q has moved through the X axis. r has moved through a direction in the third quadrant, making an angle θ with the negative X axis.

Hence, applying Law of Conservation of Momentum,

We get:

30m = m v sin θ

=> v sin θ = 30 .... (i)

Again,

40 m = m v cos θ

=> v cos θ = 40 .... (ii)

Dividing Equation (i)by (ii), we get:

[tex] tan\theta = \frac{3}{4} \\\\\implies \theta = 37^{o} [/tex]

Now, angle between p and r is asked, which can be obtained by adding 90°.

So, angle between p and r = 90 + 37 = 127°

REFER TO THE ATTACHMENT FOR THE DIAGRAM OF THE CONDITION ASSUMED.

Thanks!