a 6m long wire has a diameter 0.5 mm it's resistance is 50 ohm find the resistivity and condictiviti
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Explanation:
l=6m
d=0.5mm=5 x10^-4m
r=5/2 x10^-4m
a=πr^2=3.14 x (5/2 x 10-4m) ^2=19.625 x 10^-8m^2
we know that,
R=l/a x p
p=Ra/l=50 x 19.625 x 10^-8
=981.25 x 10-8 ohm-meter
= 9.8125 x 10^-6 ohm-meter
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