Question

A 6m long wire has diameter 0.5mm .lt resistance is 50ohm find the resistivity and conducto r

Answer 1

Solution:

Resistivity of a wire is “resistance of wire increased by area of cross component of wire” divided by “length of the wire”.

Area of the cross section of wire $=\pi\left(\frac{d}{2}\right)^{2}$

$=\pi\left(\frac{0.0005 m}{2}\right)^{2}$

$=\pi\left(\frac{0.0005 m}{2}\right)^{2}$    

So, the resistivity

= Resistance * "area of cross section / the length of wire".

$=50 \times 3.14 \times \frac{(0.00025)^{2}}{6}$

$=1.63 \times 10^{-8}$

The resistivity of a copper is $1.63 \text { times } 10^{\wedge}\{-8\}$ ohm meter. Resistivity of any metal is its characteristics property. It changes with temperature.