A 6ohm resistance wire is double up by folding. Calculate the new resistance of the wire
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Answer:
Given that
R = 6 Ohms
\(R = \frac{\rho l}{A}\)————-(1)
Wire is doubled so, Area (A) = 2A
length (l) = l/2
New Resistance will be:
\(R_{new} = \frac{\rho (\frac{l}{2})}{2A}\)
Rnew = ρl/4A
By using eqaution (1) we can simplify the above equation as
Rnew = R/4
Rnew = 6/4
Rnew = 1.5 Ohms
Hence, the new Resistance of wire is 1.5 Ohms.
Explanation:
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Answer:
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