Question

A 7.00 kg bowling ball is held 2.00 m above the ground. Using g = 9.80 m/s2, how much energy does the bowling ball have due to its position? 68.6 J 137 J 274 J 960 J

Answer 1

Since we know that ,

E= massXacceleration due to

gravityXheight

E=mgh

E= 7.00 * 9.80 * 2.00

E= 137.2 J

Answer 2

Answer : 137 J

Step-by-step explaination :

The energy that ball stores due to it's height is called Potential Energy which is denoted by the symbol of U.

U = mgh

Where, m = mass

g = acceleration due to gravity

and, h = height

Here, m = 7 kg, g = 9.8 m/s² and h = 2 m

So, U = 7 kg × 9.8 m/s² × 2 m

U = 68.6 N × 2 m

U = 137.2 J

We take 137 J as an approximate value.

Hence Option (B) 137 J is required answer.