Question

a
7. ABC is a triangle in which D is the mid-point of BC.
The perpendiculars from B and C meet the line AD
produced at X and Y. Prove that BX = CY.​

Answer 1

Answer:

Hope it helps .............

Step-by-step explanation:

In triangles BXD and CYD........

1/-∠BDX=∠CDY(Vertically opposite angles)

2/-BD=CD(D is the mid-point of BC)

3/-∠BXD=∠CYD(Both 90° given)

Hence,▲BXD≡▲CYD(By-Angle Side Angle rule)

(Here(≡)Sign means congrunt to)

Hence,BX = CY.(By-C.P.C.T)

Here,C.P.C.T means Corresponding Sides of congruent Triangles)