Question

A=-7,d=1/2 write an


a.p whose first term is a and common diffrence is d

Answer 1

a = - 7

d = 1/2

T1 = - 7

T2 = a + d = - 7 + 1/2 = - 13/2

T3 = a + 2d = - 7 + 2 /2 = - 7 + 1 = - 6

Required AP is - 7, - 13/2, - 6, - 11/2, - 5......

Answer 2

first term = a = -7



second term = a + d = -7 + 1/2
=> ( -14 + 1 ) /2 = -13/2


Third term = a + 2d = -7 + 2(1/2)
=> -7 + 1 = -6




AP = -7 , -13/2 , - 6


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