Question

a=7 d= -2 n=10 find the sum of 10 terms​

Answer 1

Answer:

tn=a+(n-1)d

t10=7+(10-1)-2

t10=7+9 into -2

t10=7-18

t10=-11

Step-by-step explanation:

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Answer 2

$\huge{\underline{ Question:}}$

$a=7 \: \: \: d= -2 \: \: \: n=10 \: \: \: \\ find \: \: the \: \: sum \: \: of \: \: 10 \: \: terms \: .$

$\huge\red{\underline{ \underline{Answer :}}}$

$Given :$

$a = 7 \\ d = - 2 \\ n = 10$

$find \: \: \: S10.$

$\boxed{Sn=\frac{1}{2}[2a + (n - 1)d]}$

$Substitute \: \: the \: \: given \: \: values.$

$S10 = \frac{1}{2} [2(7) + (10 - 1)( - 2)]$

$= \frac{1}{2} [14 + 9( - 2)]$

$= \frac{1}{2} [14 + ( - 18)]$

$= \frac{1}{2} [ - 4]$

$= \frac{ - 4 \: \: \: }{2}$

$= \large{\boxed{ \bf { - 2}}}$

$\bf \pink{Hope \: \: this \: \: helps \: \: you \: !}$