Question

a 7. Show that (p+1) is a factor of (p100-1) but is not a factor of (p11-1)​

Answer 1

Answer:

p-1 is a factor of both

Step-by-step explanation:

Let p-1 =0

then p=1

For p-1 to be a factor , the equation on substituting p=1 should be equate to 0

•f(p)= p¹⁰-1

f(1)= 1-1 =0

•f(p)= p¹¹-1

f(1)=1-1=0