A 70 kg astronaut is repairing spaceship at a height of
640 km above the surface of earth. His weight at that
location is nearly (g = 10 m s-2)
Answers
Answer:
700 newton
Explanation:
mass × acceleration = force(weight)
70 × 10 = 700 newton
therefore the weight is 700 newton
Given : A 70 kg astronaut is repairing spaceship at a height of 640 km above the surface of earth.
(g = 10 m s-2)
To Find : His weight at that location is nearly
Solution:
g' acceleration due to gravity at height h above surface of earth.
R = Radius of Earth 6400 km
g = 10 m/s² acceleration due to gravity at earth surface.
g' = g R²/(R + h)²
=> g' = g/(1 + h/R)²
=> g' = g/(1 + 640/6400)²
=> g' = g/(1 + 1/10)²
=> g' = g/(11/10)²
=> g' = 100g/121
g =10 m/s²
=> g' = 100* 10/121
=> g' = 100* 10/121
=> g' = 8.264
Weight at height 640 km above the surface of earth = mg'
= 70 x 8.264
= 578.48 N
= 578.5 N
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