A 70 Kg bike traveling at 5m/s north is hit by a 30 Kg scooter traveling 10m/s north. The bike and scooter stick together. What is their final velocity?
Answers
Explanation:
A 70 Kg bike traveling at 5m/s north is hit by a 30 Kg scooter traveling 10m/s north. The bike and scooter stick together. What is their final velocity?
4.5 Relative Motion in One and Two Dimensions | University Physics ...
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Answer:
→rPS=→rPS′+→rS′S.
The relative velocities are the time derivatives of the position vectors. Therefore,
→vPS=→vPS′+→vS′S.
The velocity of a particle relative to S is equal to its velocity relative toS′
plus the velocity ofS′
relative to S.
We can extend (Figure) to any number of reference frames. For particle P with velocities →vPA,→vPB,and→vPC
in frames A, B, and C,
→vPC=→vPA+→vAB+→vBC.
We can also see how the accelerations are related as observed in two reference frames by differentiating (Figure):
→aPS=→aPS′+→aS′S.
We see that if the velocity of S′
relative to S is a constant, then →aS′S=0
and
→aPS=→aPS′.
This says the acceleration of a particle is the same as measured by two observers moving at a constant velocity relative to each other.