Physics, asked by ekasumyan, 2 months ago

A 70 Kg bike traveling at 5m/s north is hit by a 30 Kg scooter traveling 10m/s north. The bike and scooter stick together. What is their final velocity?

Answers

Answered by devip649
4

Explanation:

A 70 Kg bike traveling at 5m/s north is hit by a 30 Kg scooter traveling 10m/s north. The bike and scooter stick together. What is their final velocity?

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Answered by skpillai636
1

Answer:

→rPS=→rPS′+→rS′S.

The relative velocities are the time derivatives of the position vectors. Therefore,

→vPS=→vPS′+→vS′S.

The velocity of a particle relative to S is equal to its velocity relative toS′

plus the velocity ofS′

relative to S.

We can extend (Figure) to any number of reference frames. For particle P with velocities →vPA,→vPB,and→vPC

in frames A, B, and C,

→vPC=→vPA+→vAB+→vBC.

We can also see how the accelerations are related as observed in two reference frames by differentiating (Figure):

→aPS=→aPS′+→aS′S.

We see that if the velocity of S′

relative to S is a constant, then →aS′S=0

and

→aPS=→aPS′.

This says the acceleration of a particle is the same as measured by two observers moving at a constant velocity relative to each other.

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