Question

a 70 kg man pushes a 50 kg Man by a force of 50n by what force has the 50 kg man pushed the other man

Answer 1

Given condition,

Mass of the man = 70kg

(F) Force used by the man to push another man of mass 50 kg = 50 N.

Normal reaction act on 50 kg man = mass × acceleration due to gravity.

= 50 × 10 N

= 500 N

Using the Formula, Friction = r N ,

where,

N is normal reaction,

r is coefficient of static friction

In Ideal Condition, Frictional Force = Normal Reaction Force.

∴ 50 = r × N

50 = r × 500

⇒ r = 0.1

∴ coefficient of static Friction = 0.1

Let the Force acting on the man of mass 50 kg by the man of mass 70 kg be x.

∴ x = static Friction

x = coefficient of static friction × normal reaction act on 70 kg man

x = 0.1 × 70 × 10

x = 70 N

Hence, the Force of 70 N acts on the body of mass 50 kg by the man of 70 kg is 70 N.

Hope it helps.

Answer 2

Given:

Mass of man1 = 70 kg

Mass of man2 = 50 kg

Force = 50 N

To find:

The force needed by man2 to push man1

Solution:

By formula,

Normal= Mass * Gravity

Where,

Gravity = 9.8 m / s

Substituting,

50 × 9.8

Normal = 490 N

To find friction,

Friction = r * Normal  

Where,  

r is coefficient of static friction

We know,

Ideally,

Frictional Force = Normal Reaction Force.  

∴ 50 = r × N  

50 = r × 490

r = 0.102

Hence,

Force = 0.102 × 70 × 9.8

Force = 69.9 N

Therefore, Force ≅ 70 N

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