Question

A 700 N man and a 450 N woman have the same momentum. What is the ratio of the
man's kinetic energy to that of the woman?​

Answer 1

Answer:

Given:

• A 700 N man and a 450 N woman have the same momentum.

To find:

• Ratio of their kinetic energy.

Solution:

Weight = mass × Net acceleration

Now, Net acceleration will be constant for both man and woman.

Hence, m (m)/m (w) = 700/450

= 14/9 ... (1)

» Momentum of man = Momentum of woman

» m (m) v (m) = m (w) v (w)

» v (m) / v (w) = m (w) / m (m) ... (2)

$kinetic \: energy \: = \frac{1}{2}m {v}^{2}$

Ratio = m (m) v² (m) / m (w) v² (w)

= m (w)/m (m) ... from (2)

= 9/14 ... from (1)