Question

A 70kg man is sea is being lifted by a helicopter with the help of a rope which can bear a maximum tension of 100kg wt . with what maximum acceleration the break​

Answer 1

Answer:

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Explanation:

A 70 kg man in sea is being lifted by a helicopter with the help of a rope which can bear a maximum tension of 100kg-wt. With what maximum acceleartion the helicopter should rise so that the rope may not break. Let a be the required acceleration. Therefore, maximum acceleration without breaking the rope is 4.286 m/s^2

Answer 2

Complete question should be like this-

A 70 kg man in sea is being lifted by a helicopter with the help of a rope which can bear a maximum tension of 100kg-wt. With what maximum acceleartion the helicopter should rise so that the rope may not break.

● Answer-

a = 4.286 m/s^2

● Explanation-

# Given-

T = 100 kg-wt = 1000 N

m = 70 kg

# Solution-

Let a be the required acceleration.

Then, for maximum tension,

ma = T - mg

70a = 1000 - 70×10

70a = 300

a = 4.286 m/s^2

Therefore, maximum acceleration without breaking the rope is 4.286 m/s^2.

Hope this helps...

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