Question

A 70kg man Runs up a hill through a height of 3m in 2sec ,If velocity is 1m/s then ,Kinetic energyap
A)1/2K.E
B)1/4K.E
C)1/8KE
D)1/3KE​

Answer 1

Given:-

• Mass, m = 70kg

• Height, h = 3m

• velocity,v = 1m/s

• Time taken ,t = 2

To Find:-

• Kinetic energy.K.E

Solution:-

Here , Kinetic Energy change into Potential Energy.

• K.E = mgh

Substitute the value we get

→ K.E = 70×3×10

→ K.E = 210×10

→ K.E = 2100 J

Therefore, the kinetic energy of man is 2100J.

Additional Information!!

Some equation of motion are

⟹ v = u +at

⟹s = ut +1/2at².

⟹ v² = u² + 2as

Here,

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement or Distance

t is the time taken

Answer 2

Answer:

• The required kinetic energy = 2100 joule

Given:

• A 70kg man Runs up a hill through a height of 3m in 2sec ,If velocity is 1m/s.

Need to find:

• The required kinetic energy = ?

Solution:

Formula used here:

• Kinetic energy = m × g × h

Putting the values:

➜ Required kinetic energy = 70 × 3 × 10

➜ Required kinetic energy = 70 × 30

➜ Required kinetic energy = 2100 joule

Therefore:

• The required kinetic energy = 2100 joule

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