Question

A 72 kg parachutist has a speed of 92 m/s at an altitude of 1102 m above the ground.
a. Determine the kinetic energy possossed by the parachutist.
b. Determine the potential energy possessed by the parachutist.
c. Determine the total mechanical energy possessed by the parachutist . ​

Answer 1

Answer:

KE = 304704J, PE = 777571.2J, ME = 1082275.2J

Explanation:

a. ans:-  KE= $1/2mv^{2}$

                  = 1/2*72*92*92l

                  = 304704 J

b. ans:-   PE=  mgh

                   =  72*9.8*1102

                   =  777571.2 J

c. ans:-    ME= potential energy + kinetic energy

                    =  777571.2 + 304704

                    = 1082275.2 J

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Answer 2

Answer:

as shown in pic answer is a=304704j.

b=777571.2j.

c=182275.2j.

Answer 3

Answer:

as shown in pic answer is a=304704j.

b=777571.2j.

c=182275.2j.