Question

A 72 L mixture contains milk and water in the ratio 7: 5. How much more milk is to be added to the
mixture so that the new ratio of milk and water becomes 9 : 5?step wise pls​

Answer 1

Answer:

72 Liters mixture contains milk and water in the ration of 7:5

milk : water = 7 : 5

Therefore milk content in the mixture is = (Milk Ratio / Sum of Both Ratios) x Total Mixture of Milk and Water = Amount of milk in the mixture

Therefore milk content in the mixture is = (7 / 12) x 72 = 42 Liters of milk in the mixture

The new ratio of milk and water we want to achieve is 9:5

milk : water = 9 : 5

If you observe the question, we are trying the increase the ratio or the percentage of milk in the ratio by keeping the water ratio constant, that means the milk will added to increase the ratio and the water content will remain the same (no change)

The new ratio that we are trying to achieve is:

milk : water = 9 : 5

Let x be the amount of milk we are adding to the mixture

Therefore the milk content in the new mixture will be:

(Milk Ratio / Sum of Both Ratios) x (Previous Mixture of Milk and Water + Amount of milk added) = Amount of milk in the previous mixture + Amount of milk added

(9 / 14) * (72 + x) = 42 + x

((9 * 72) + (9 * x) ) / 14 = 42 + x

(648 + 9x) = 14 * (42 + x)

(648 + 9x) = (14 * 42 + 14 * x)

(648 + 9x) = (588 = 14x)

648 - 588 = 14x - 9x

5x = 60

x = 60 / 5

x = 12 Liters

Hence 12 Liters of milk need to be added to make the new mixture in the ratio of 9 : 5

Step-by-step explanation: