A 72L mixture contains milk and water in the ratio 7:5. how much more milk is to be added to the mixture so that the new ratio of milk and water becomes 9:5?
Answers
In the above Question , the following information is given -
A 72L mixture contains milk and water in the ratio 7:5.
To find -
How much more milk is to be added to the mixture so that the new ratio of milk and water becomes 9:5?
Solution -
Here , A 72L mixture contains milk and water in the ratio 7:5.
Let the amount of milk and water in the mixture be 7x and 5x respectively .
So ,
7x + 5x = 72
=> 12x = 72
=> x = 6
Amount of milk in the mixture
=> 7x
=> 42 litres .
Amount of water In the mixture -
=> 5x
=> 32 litres.
Now , let the amount of milk that is added = x litres.
=> [ 42 + x ] / [ 32 ] = [ 9 / 5 ]
=> 5 ( 42 + x ) = 32 × 9
=> 210 + 5x = 288
=> 5x = 78
=> x = 15.4 litres.
This is the required answer .
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