Math, asked by simpalkatiyar1, 9 months ago

A 72L mixture contains milk and water in the ratio 7:5. how much more milk is to be added to the mixture so that the new ratio of milk and water becomes 9:5? pleaseeeeeeeeeeeee any one tell answer​

Answers

Answered by prudvireddy
10

Answer:

12 litres

Step-by-step explanation:

milk in mixture = 72 (7 / 12)

= 6 x 7

= 42 lit

water in mixture = 72 (5 / 12)

= 6 x 5

= 30 lit

let x litres of milk be added then ratio becomes 9:5

(42 + x) / (30) = 9 / 5

5 (42 + x) = 9 (30)

210 + 5x = 270

5x = 270 - 210

5x = 60

x = 12

12L of milk is to be added

Answered by rkarthikrampandian
1

Answer:

12L

Step-by-step explanation:

The ratio of milk : water = 7:5

Let the ratios be 7x and 5x

7x+5x=72litres

12x=72

X=72/12

X = 6

Therefore , First part =7x =7x6=42

Second part =5x= 5x6=30

According to the question

42x+X/30 =9/5

42+X=9/5X30

=54-42

X=12litres

And: Therefore 12 l of milk is to be added

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