A 72L mixture contains milk and water in the ratio 7:5. how much more milk is to be added to the mixture so that the new ratio of milk and water becomes 9:5? pleaseeeeeeeeeeeee any one tell answer
Answers
Answered by
10
Answer:
12 litres
Step-by-step explanation:
milk in mixture = 72 (7 / 12)
= 6 x 7
= 42 lit
water in mixture = 72 (5 / 12)
= 6 x 5
= 30 lit
let x litres of milk be added then ratio becomes 9:5
(42 + x) / (30) = 9 / 5
5 (42 + x) = 9 (30)
210 + 5x = 270
5x = 270 - 210
5x = 60
x = 12
12L of milk is to be added
Answered by
1
Answer:
12L
Step-by-step explanation:
The ratio of milk : water = 7:5
Let the ratios be 7x and 5x
7x+5x=72litres
12x=72
X=72/12
X = 6
Therefore , First part =7x =7x6=42
Second part =5x= 5x6=30
According to the question
42x+X/30 =9/5
42+X=9/5X30
=54-42
X=12litres
And: Therefore 12 l of milk is to be added
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