Question

A. 740-kg elevator accelerated upward at 1.1m/s^2 ,pulled by a cable of negligible mass. Find the tension force in the cable.


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Answer 1

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Given :-

Mass of elevator (M) = 740 kg

Acceleration (A) = 1.1m²

Acceleration due to gravity (G) = 9.8 m/s²

To Find :-

Tension force

Solution :-

As we know that

$\bf \: T = m(g + a)T=m(g+a)</p><p>$

Here,

T = Tension force

M = Mass

G = Acceleration due to gravity

A = Acceleration

Putting values

$</p><p>\sf \: T = 740(9.8 + 1.1)T=740(9.8+1.1)</p><p>$

$</p><p>\sf \: T = 740 \times 10.9T=740×10.9$

$</p><p>\sf \: T = 8066 \: N T=8066N$

Therefore,

Tension force of elevator = 8066 Newton.

I hope it is helpful for you

@ Aman jha