Question

A 747 jet, traveling at a velocity of 70.0 meters per second north, touches down on a runway. The jet slows to rest at the rate of 2.00 meters per second squared. What is the distance in meters the jet travels before coming to rest?

Answer 1

Answer:

A jetliner, traveling northward, is landing with a speed of 69 m/s. Once the jet touches down, it has 750 m of runway in which to reduce its speed to 6.1 m/s. Compute the average acceleration (magnitude and direction) of the plane during landing.

We know , , and

We want . We know that acceleration is reducing speed so it must act in the opposite direction or south. The equation we will use is

This equation removes the vector character so we must understand that a must be negative, which makes the equation

Now solving for a