Question

A 75 kg refrigerator is located on the 70th floor of a skyscaper (300 meter above the ground).What is the potential energy of the ground?use GUFSA METHOD

Answer 1

Answer:

Potential energy = (mass) x (gravity) x (height above the reference)

Relative to the 70th floor, on which the refrigerator is standing,

PE = (75 kg) x (9.8 m/s²) x (0) = 0 joules .

Relative to the 35th floor, halfway up to where the fridge is standing,

PE = (75 kg) x (9.8 m/s²) x (150 m) = 110,250 joules .

Relative to the ground,

PE = (75 kg) x (9.8 m/s²) x (300 m) = 220,500 joules .