Math, asked by amitsrivastava1998, 7 months ago

A 75 m long piece of wire is cut into two
parts, one being 30 m long. If each part is
bent to form a square, what is the ratio of
the area of the larger square to the smaller
square?
a 16:9
b. 4:9
C. 9:16
d. 9:4​

Answers

Answered by booraneelam1
30

Answer:

I think 16:9 is correct may be it incorrect

Answered by Anonymous
33

Given,

The total length of the wire is 75 metres.

Length of one piece of wire is 30 metres

To find,

Ratio of the area of largest square to the smallest square.

Solution,

The length of the another piece of wire

= Total length - Length of one piece of wire

= 75 - 30

= 45 metres

Length of one side of the smaller square = 30/4 = 7.5 metres

Area of the smaller square = (7.5)² = 56.25 m²

Length of one side of the bigger square = 45/4 = 11.25 metres

Area of the bigger square = (11.25)² = 126.5625 m²

The ratio = 56.25 : 126.5625 = 4:9

Hence, the ratio is 4:9

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