A 75 m long piece of wire is cut into two
parts, one being 30 m long. If each part is
bent to form a square, what is the ratio of
the area of the larger square to the smaller
square?
a 16:9
b. 4:9
C. 9:16
d. 9:4
Answers
Answered by
30
Answer:
I think 16:9 is correct may be it incorrect
Answered by
33
Given,
The total length of the wire is 75 metres.
Length of one piece of wire is 30 metres
To find,
Ratio of the area of largest square to the smallest square.
Solution,
The length of the another piece of wire
= Total length - Length of one piece of wire
= 75 - 30
= 45 metres
Length of one side of the smaller square = 30/4 = 7.5 metres
Area of the smaller square = (7.5)² = 56.25 m²
Length of one side of the bigger square = 45/4 = 11.25 metres
Area of the bigger square = (11.25)² = 126.5625 m²
The ratio = 56.25 : 126.5625 = 4:9
Hence, the ratio is 4:9
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